String dirName = "C:/Photos/Maldives"; //in my dreams
String fileNameExt = ".jpg"; //JPEG format
String fileNamePref = "RIMG"; //just blank to rename all photos
String fileNameFmt = "yyyyMMdd_HHmmss"; //e.g. 20161018_161534 for October 18, 2016 4:15:34 PM (should be unique enough!)

File directory = new File(dirName);
File[] photos = directory.listFiles();

for(File photo : photos) {
   String filename = photo.getName();

   if(filename.toLowerCase().endsWith(fileNameExt) && filename.startsWith(fileNamePref)) {
      SimpleDateFormat sdf = new SimpleDateFormat(fileNameFmt);
      String newFilename = sdf.format(photo.lastModified()) + fileNameExt;
      File renamedPhoto = new File(photo.getParent() + "/" + newFilename);

      if(!photo.renameTo(renamedPhoto)) {
         System.out.println("Failed to rename: " + photo.getAbsolutePath());
      }
   } else {
      System.out.println("Not a " + fileNamePref + "*" + fileNameExt + ": " + photo.getAbsolutePath());
   }
}

This is under the assumption that the date and time in your devices have been set correctly. Different time zones are no longer within the scope of this post but is accommodated in—apparently someone already thought of the same—Renaming jpeg files with date+time stamp. Ideally, all photos should be renamed successfully since no two photos can be taken at exactly the same time (burst shots are another story). But with multiple cameras, there can simply be conflict sometimes. Lastly, you should be careful when copying or moving photos because sometimes the Last Modified data are changed to the date you copied or moved them. Should that be the case, the given source code no longer holds any value.

The post Renaming Photos by Timestamp appeared first on Beer & Skittles.

package letter;

public class LetterGenerator {
   public static void main(String[] args) {
      int dim = 7;

      for(int i = 0; i < dim; i++) {
         for(int j = 0; j < dim; j++) {
            if(i == j || i + j == dim - 1) {
               System.out.print("*");
            } else {
               System.out.print(" ");
            }
         }

         System.out.println();
      }

      System.out.println();

      for(int i = 0; i < dim; i++) {
         for(int j = 0; j < dim; j++) {
            if(((i == j || i + j == dim - 1) && i < dim / 2 + 1) || (i > dim / 2 && j == dim / 2)) {
               System.out.print("*");
            } else {
               System.out.print(" ");
            }
         }

         System.out.println();
      }

      System.out.println();

      for(int i = 0; i < dim; i++) {
         for(int j = 0; j < dim; j++) {
            if(i == 0 || i + j == dim - 1 || i == dim - 1) {
               System.out.print("*");
            } else {
               System.out.print(" ");
            }
         }

         System.out.println();
      }
   }
}

The post Printing XYZ in Java using Asterisks appeared first on Beer & Skittles.

In my case, the checking that the end date should be greater than the start date was already handled somewhere else so I already skipped it. Also, instead of actual Dates, I only needed Strings (but I do intend to convert this into a generic utility class). So, yeah, here you go:

final SimpleDateFormat DATE_FORMAT = new SimpleDateFormat("yyyy/MM/dd");
Calendar startDate = Calendar.getInstance();
Calendar endDate = Calendar.getInstance();

try {
   startDate.setTime(DATE_FORMAT.parse("2012/08/01"));
   endDate.setTime(DATE_FORMAT.parse("2012/08/10"));

   ArrayList<String> includedDates = new ArrayList<String>();

   while(!startDate.equals(endDate)) {
      String date = DATE_FORMAT.format(startDate.getTime());
      includedDates.add(date);
      startDate.add(Calendar.DATE, 1);
   } includedDates.add(DATE_FORMAT.format(endDate.getTime()));

   for(String date : includedDates) {
      System.out.println(date);
   }
} catch(Exception e) {}

Today I checked back on the supposedly second working solution I cited above, copy-pasted the code, and successfully ran it. :wtf:

The post Generating Dates Between Start and End in Java appeared first on Beer & Skittles.

• User only inputs characters (and spaces!) included in the given alphanumeric set.
• Numeric characters result in uppercase plain/cipher characters.
• Encryption/decryption key cannot have a space.

VigenereCipher.java

private static final char[] alphnum = {
   'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L',
   'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X',
   'Y', 'Z', '0', '1', '2', '3', '4', '5', '6', '7', '8', '9'
};

The post Vigenere Cipher in Java appeared first on Beer & Skittles.

Feedback from friends, positively spoken and written (statuses), kept me wondering what the movie really was all about. I never set my eyes on it because the trailer didn’t intrigue nor enlighten me as a layman. But as it turns out, it’s way more nerve-wracking than you can think of.

After seeing a pseudocode post from my adviser and visiting the big screen, I knew I just had to make my own — a recursive one. To experience euphoria, I dug an implementation. What the program does is very simple. It asks for the levels of dream you wish to experience, and then prints out the time spent on each level. You’ll see…

Inception.java

void dream(int level) {
   if(level <= 0) {
      return;
   }

   try {
      System.out.print("Level " + level + ": ");
      long startTime = System.currentTimeMillis();
      Thread.sleep(1000*level);
      long endTime = System.currentTimeMillis();
      System.out.println((endTime-startTime) + " ms");
   } catch(InterruptedException ie) {}

   dream(level-1);
}

The post Java Implementation of “Inception” appeared first on Beer & Skittles.